替换图片链接
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@@ -170,7 +170,7 @@ for (int j = 0; j <= word2.size(); j++) dp[0][j] = j;
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可以看出dp[i][j]是依赖左方,上方和左上方元素的,如图:
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所以在dp矩阵中一定是从左到右从上到下去遍历。
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@@ -194,7 +194,7 @@ for (int i = 1; i <= word1.size(); i++) {
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以示例1为例,输入:`word1 = "horse", word2 = "ros"`为例,dp矩阵状态图如下:
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以上动规五部分析完毕,C++代码如下:
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