Update

problems/背包理论基础01背包-1.md

@@ -438,6 +438,58 @@ print(dp[n - 1][bagweight])
 ### Go
 
 ```go
+package main
+
+import (
+    "fmt"
+)
+
+func main() {
+    var n, bagweight int // bagweight代表行李箱空间
+    fmt.Scan(&n, &bagweight)
+
+    weight := make([]int, n) // 存储每件物品所占空间
+    value := make([]int, n)  // 存储每件物品价值
+
+    for i := 0; i < n; i++ {
+        fmt.Scan(&weight[i])
+    }
+    for j := 0; j < n; j++ {
+        fmt.Scan(&value[j])
+    }
+    // dp数组, dp[i][j]代表行李箱空间为j的情况下,从下标为[0, i]的物品里面任意取,能达到的最大价值
+    dp := make([][]int, n)
+    for i := range dp {
+        dp[i] = make([]int, bagweight + 1)
+    }
+
+    // 初始化, 因为需要用到dp[i - 1]的值
+    // j < weight[0]已在上方被初始化为0
+    // j >= weight[0]的值就初始化为value[0]
+    for j := weight[0]; j <= bagweight; j++ {
+        dp[0][j] = value[0]
+    }
+
+    for i := 1; i < n; i++ { // 遍历科研物品
+        for j := 0; j <= bagweight; j++ { // 遍历行李箱容量
+            if j < weight[i] {
+                dp[i][j] = dp[i-1][j] // 如果装不下这个物品,那么就继承dp[i - 1][j]的值
+            } else {
+                dp[i][j] = max(dp[i-1][j], dp[i-1][j-weight[i]]+value[i])
+            }
+        }
+    }
+
+    fmt.Println(dp[n-1][bagweight])
+}
+
+func max(x, y int) int {
+    if x > y {
+        return x
+    }
+    return y
+}
+
 ```
 
 ### Javascript