移除多余的sql方法

This commit is contained in:
lhd 2024-08-06 15:58:42 +08:00
parent 3308fe5ee6
commit 81bae22ed0
2 changed files with 0 additions and 35 deletions

View File

@ -86,22 +86,6 @@ public interface OrderMapper extends BaseMapper<Order> {
*/
Long countOrderDetail(@Param("orderParam") OrderParam orderParam);
/**
* 根据店铺id和用户id获取购买过的商品id列表
* @param shopId
* @param userId
* @return
*/
List<Long> listBoughtProdByUserIdAndShopId(@Param("shopId") Long shopId, @Param("userId") String userId);
/**
* 根据参数计算用户消费信息
* @param shopId
* @param userId
* @return
*/
UserShoppingDataDto calculateUserInShopData(@Param("shopId") Long shopId, @Param("userId") String userId);
/**
* 根据用户id和订单状态获取订单列表
* @param adapter

View File

@ -288,25 +288,6 @@
</where>
</select>
<select id="listBoughtProdByUserIdAndShopId" resultType="long">
select
oi.prod_id
from tz_order_item oi
join tz_order o on o.order_number = oi.order_number
where o.user_id=#{userId} and o.shop_id = #{shopId} and (o.status = 4 or o.status = 5)
</select>
<select id="calculateUserInShopData" resultType="com.yami.shop.bean.distribution.UserShoppingDataDto">
select
count(o.order_number) as expense_number,
ifnull(SUM(o.actual_total),0) as expense_amount
from tz_order o
where o.user_id=#{userId} and o.shop_id = #{shopId} and (o.status = 4 or o.status = 5)
</select>
<select id="listMyOrderByUserIdAndStatus" resultMap="MyOrderMap">
SELECT o.actual_total,oi.pic,oi.price,oi.prod_name,oi.sku_name,oi.prod_count,o.status,o.order_number
FROM (